Capacitor charge & ripple calculator

Interactive engineering and procurement calculator. Instant client-side computation with no sign-up.

Charge / discharge

Time constant (τ)

τ = R × C

1000 ms

Time to 63.2 %

1τ = 63.2 % of the supply

1000 ms

Time to 95.0 %

3τ = 95.0 % of the supply

3 s

Time to 99.3 %

5τ = 99.3 % of the supply

5 s

Stored energy

E = ½ × C × V²

1.25 mJ

Rectifier output ripple

Ripple voltage (Vr)

Full-wave — I ÷ (2 × 50 × C)

50 V

Ripple as % of output

Vr ÷ V × 100

416.7 %

Required C for target ripple

C = I ÷ (2 × 50 × Vr)

10 mF

About the model

Charging a capacitor through a resistor follows the exponential V(t) = V·(1 − e^(−t/τ)) with τ = R·C: after one time constant the capacitor is at 63.2 %, after 3τ at 95 %, and after 5τ it is effectively full at 99.3 %. The stored energy E = ½·C·V² is the same expression used for the inrush peak when the capacitor first connects to the supply.

On a rectified rail the capacitor recharges at the ripple peaks and supplies the load between them, so the peak-to-peak ripple is Vr = I / (2·f·C) for a full-wave rectifier (charging twice per cycle) and I / (f·C) for half-wave. Halving the ripple needs double the capacitance — or double the ripple frequency, which is why full-wave and higher-mains designs use smaller bulk capacitors. The model ignores capacitor ESR and the real conduction angle, which add a few tens of percent on top.

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