BJT voltage divider bias calculator

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Bias design

Results

R1 — divider upper

R1 = R_B·Vcc ÷ Vb

30 kΩ

R2 — divider lower

R2 = R_B·Vcc ÷ (Vcc − Vb)

5.6 kΩ

Emitter resistor (Re)

Re = Ve ÷ Ic

240 Ω

Collector resistor (Rc)

Rc = (Vcc − Vce − Ve) ÷ Ic

1.2 kΩ

Divider current

Vcc ÷ (R1 + R2) — ~10× the base current

0.0003371 A

Operating point Ic

Simulated with nearest-E24 parts

4.49 mA

Operating point Vce

Simulated with nearest-E24 parts

5.54 V

β sensitivity

Ic holds within ±10%
βIc (mA)Vce (V)vs nominal
1004.16.08+8.56%
2004.495.540%
4004.715.22+4.91%

Ic stays within ±10% when β is halved or doubled — the divider bias is doing its job.

About the model

The four-resistor network sets a Thevenin base voltage with R1 and R2 while Re degenerates the emitter. Because the divider current is roughly ten times the base current (R_B = β·Re/10), the base sits near a fixed voltage and Ic ≈ Ve/Re barely moves with β — the classic trade-off between bias stability and the power the divider wastes. Rc is then sized from the headroom left between Vcc, Vce and Ve.

Real parts spread β far wider than the datasheet typical, so prototypes should always be measured. The operating point above is simulated with the nearest E24 resistors.

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